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NEETPhysicsCapacitance

A circuit consists of a battery of EMF 18 V and internal resistance 1 connected in series with a resistor R₁ . The other end of R₁ is connected to a parallel combination of two branches. The first branch has a resistor R₂ = 2 . The second branch has a capacitor C = 3 F in series with a resistor R₃ = 5 . The circuit is completed by connecting the parallel combination back to the battery. If the steady-state charge on

Options

  1. A3
  2. B4
  3. C2
  4. D5

Correct answer

A. 3

Step-by-step solution

In steady state, the capacitor is fully charged and acts as an open circuit, so no current flows through the branch containing R₃ and C . The potential difference across the capacitor is given by V_C = Q C = 18 C 3 F = 6 V . Since there is no current through R₃ , the voltage drop across R₃ is zero. Therefore, the potential difference across the entire parallel combination is equal to the voltage across the capacitor, which is 6 V . This same potential difference of 6 V appears across the first branch containing R₂

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