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NEET
Exam
NEET
Subject
Physics
Chapter
Capacitance

NEET · Physics · Capacitance

Given below are two statements: one is labelled as Assertion (A)...

Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R).

Assertion (A): When a capacitor C1C_1 is connected in parallel with a series combination of two identical capacitors (C2C_2 and C3C_3, where C1=C2=C3C_1 = C_2 = C_3), the charge stored in C1C_1 is half the charge stored in C2C_2.
Reason (R): In a parallel circuit, the branch with the lower equivalent capacitance draws proportionally less charge from the source because Q∝CQ \propto C for a constant potential difference.

In the light of the above statements, choose the most appropriate answer from the options given below:

Options

  1. ABoth Assertion (A) and Reason (R) are correct and Reason (R) is the correct explanation of Assertion (A)
  2. BBoth Assertion (A) and Reason (R) are correct but Reason (R) is not the correct explanation of Assertion (A)
  3. CAssertion (A) is correct but Reason (R) is not correct
  4. DAssertion (A) is not correct but Reason (R) is correct

Correct answer

D. Assertion (A) is not correct but Reason (R) is correct

Step-by-step solution

Let the capacitance of each capacitor be CC. The equivalent capacitance of the series branch containing C2C_2 and C3C_3 is C2\dfrac{C}{2}.

Since C1C_1 is in parallel with this series branch, the potential difference VV across both branches is the same.
The charge stored in C1C_1 is Q1=C1V=CVQ_1 = C_1 V = CV.
The charge drawn by the series branch is Qs=CsV=(C2)VQ_s = C_s V = \left(\dfrac{C}{2}\right)V.
In a series combination, the charge on each capacitor is equal to the total charge of that branch. Therefore, the charge on C2C_2 is Q2=(C2)VQ_2 = \left(\dfrac{C}{2}\right)V.

Comparing the charges, Q1=2Q2Q_1 = 2Q_2. The charge stored in C1C_1 is twice the charge stored in C2C_2, not half. Thus, Assertion (A) is false.

Reason (R) is a correct statement of principle. For branches in parallel, the potential difference VV is constant, so the charge Q=CVQ = CV is directly proportional to the equivalent capacitance of the branch. The branch with lower capacitance draws less charge.

Answer: Assertion (A) is not correct but Reason (R) is correct
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