In the given figure, the capacitance C₁, C₃, C₄ , C ₅ have a capacitance 4 F each. If the capacitor C₂ has a capacitance 10 F , then effective capacitance between A and B will be

Step-by-step solution

Capacitance of capacitors C₁, C₃, C₄ , C₅=4 F each and capacitance of capacitor C₂=10 F . If a battery is applied across A and B , the points b and c will be at the same potential (since C₁=C₄=C₃=C₅=4 F ). Therefore no charge flows through C₂ . We have the capacitors C₁ and C₅ in series. Therefore their equivalent capacitance, C^ = C₁ C₅ C₁+C₅ = 4 4 4+4 =2 F Similarly, C₄ and C₃ are in series. Therefore their equivalent capacitance, C^ = C₃ C₄ C₃+C₄ = 4 4 4+4 =2 F . Now C^ and C^ are in parallel. Therefore effectiv