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NEETPhysicsCurrent Electricity

A battery of EMF 18 V and internal resistance 2 is connected in a single closed loop with another battery of EMF 6 V and internal resistance 1 . The two batteries are connected in opposition. An external resistor of 9 is also connected in series in the loop. What is the potential difference across the terminals of the 6 V battery?

Options

  1. A5 V
  2. B7 V
  3. C16 V
  4. D6 V

Correct answer

B. 7 V

Step-by-step solution

The two batteries are connected in opposition, so their net EMF is the difference between their individual EMFs: E_ net = 18 V - 6 V = 12 V . The total resistance in the circuit is the sum of the external resistance and the internal resistances of both batteries: R_ net = 9 + 2 + 1 = 12 . The current in the circuit is: I = E_ net R_ net = 12 12 = 1 A . Since the 18 V battery dominates, the current flows out of its positive terminal and enters the positive terminal of the 6 V battery. This means the 6 V battery is b

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