NEETPhysicsCurrent Electricity
Match List-I with List-II. List-I (Pairs of resistors in parallel) List-II (Fraction of total main current passing through the first resistor) (A) 2 and 2 (I) 4 5 (B) 3 and 6 (II) 3 5 (C) 1 and 4 (III) 1 2 (D) 2 and 3 (IV) 2 3 Choose the correct answer from the options given below:
Options
- A(A) - (III), (B) - (IV), (C) - (I), (D) - (II)
- B(A) - (III), (B) - (I), (C) - (IV), (D) - (II)
- C(A) - (III), (B) - (II), (C) - (IV), (D) - (I)
- D(A) - (I), (B) - (III), (C) - (II), (D) - (IV)
Correct answer
A. (A) - (III), (B) - (IV), (C) - (I), (D) - (II)
Step-by-step solution
When two resistors R₁ and R₂ are connected in parallel, the current I₁ passing through the first resistor R₁ is given by the current division rule: I₁ = I_ total R₂ R₁ + R₂ For (A) 2 and 2 : Fraction = 2 2 + 2 = 1 2 . This matches (III). For (B) 3 and 6 : Fraction = 6 3 + 6 = 6 9 = 2 3 . This matches (IV). For (C) 1 and 4 : Fraction = 4 1 + 4 = 4 5 . This matches (I). For (D) 2 and 3 : Fraction = 3 2 + 3 = 3 5 . This matches (II). Therefore, the correct matching is (A) - (III), (B) - (IV), (C) - (I), (D) - (II). An