In a meter bridge experiment, a resistance of 10 is connected in the left gap and a resistance of 15 is connected in the right gap. The end corrections at the left end A and the right end B are found to be 1 cm and 2 cm respectively. The observed balance length l on the meter scale, measured from the left end A , is:

Step-by-step solution

Let R₁ = 10 and R₂ = 15 . The meter bridge formula accounting for end corrections e₁ and e₂ is given by: R₁ R₂ = l + e₁ 100 - l + e₂ Substituting the given values: 10 15 = l + 1 100 - l + 2 2 3 = l + 1 102 - l Cross-multiplying yields: 2(102 - l) = 3(l + 1) 204 - 2l = 3l + 3 201 = 5l l = 40.2 cm Ignoring end corrections would lead to 40.0 cm , and subtracting them instead of adding would lead to 39.8 cm . Answer: 40.2 cm