NEETPhysicsCurrent Electricity
A student attempts to measure a very low unknown resistance (around 0.01 ) using a standard Wheatstone bridge. Even though a perfect null point is obtained and the standard formula P Q = R S is applied correctly, the calculated value of the unknown resistance is found to be highly inaccurate. What is the fundamental physical reason for this inaccuracy in this specific regime?
Options
- AThe galvanometer cannot detect the extremely small currents that flow in the circuit when measuring low resist
- BThe bridge principle mathematically breaks down and becomes invalid for resistance values below one ohm.
- CThe resistances of the connecting wires and contact points become comparable to the unknown resistance.
- DThe battery gets short-circuited by the low resistance arms, causing its terminal voltage to drop to zero.
Correct answer
C. The resistances of the connecting wires and contact points become comparable to the unknown resistance.
Step-by-step solution
The standard Wheatstone bridge formula P Q = R S assumes that the connecting wires and the contact points at the terminals have zero resistance. When measuring normal or high resistances, these tiny contact and lead resistances (usually a fraction of an ohm) are negligible and do not significantly affect the result. However, when measuring a very low resistance (like 0.01 ), the contact and lead resistances become comparable to or even greater than the unknown resistance itself. This introduces a massive percentage