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NEETPhysicsCurrent Electricity

A steady current divides into two parallel resistors, R₁ and R₂ . If 20 % of the total current flows through R₁ , what is the ratio of their resistances R₁ R₂ ?

Options

  1. A1 4
  2. B1 5
  3. C4
  4. D5

Correct answer

C. 4

Step-by-step solution

Let the total current be I . The current flowing through R₁ is I₁ = 0.2I . Using the current division rule for two parallel branches, the current through R₁ is given by: I₁ = I R₂ R₁ + R₂ Substituting the given value: 0.2I = I R₂ R₁ + R₂ 1 5 = R₂ R₁ + R₂ Cross-multiplying yields: R₁ + R₂ = 5R₂ R₁ = 4R₂ Therefore, the ratio R₁ R₂ = 4 . Answer: 4

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