A galvanometer has a coil resistance of 49.5 and shows full scale deflection for a current of 10 mA . If it is provided with a shunt resistance of 0.5 , what is the maximum current that can be measured by the resulting ammeter?

Step-by-step solution

Given G = 49.5 , I_g = 10 mA = 10 10⁻³ A , and S = 0.5 . The maximum current I that the ammeter can measure is related to the galvanometer current I_g by the principle of parallel circuits: I_g G = (I - I_g) S Rearranging for I gives: I = I_g (1 + G S ) Substituting the given values: I = 10 10⁻³ (1 + 49.5 0.5 ) I = 10⁻² (1 + 99) I = 10⁻² 100 = 1.0 A Answer: 1.0 A