A galvanometer of resistance 50 is converted into an ammeter capable of measuring up to 1.01 A by connecting a shunt of 0.5 . What series resistance is required to convert the same galvanometer into a voltmeter capable of measuring up to 10 V ?

Step-by-step solution

First, find the full-scale deflection current I_g of the galvanometer using the ammeter data. For an ammeter, the shunt resistance S is given by: S = I_g G I - I_g Rearranging to solve for I_g : I_g = I S G + S Substituting the values I = 1.01 A , G = 50 , and S = 0.5 : I_g = 1.01 0.5 50 + 0.5 = 0.505 50.5 = 0.01 A Next, find the series resistance R required to convert the galvanometer into a voltmeter of range V = 10 V . The formula for voltmeter conversion is: R = V I_g - G Substituting the values: R = 10 0.01 -