NEET2018PhysicsCurrent ElectricityActual
In the circuit shown, the current through the 5 resistor is
Options
- A8 3 ~A
- B9 13 ~A
- C4 13 ~A
- D1 3 ~A
Correct answer
D. 1 3 ~A
Step-by-step solution
Applying Kirchhoff's second law for closed loop A E F B A , we get - (I₁+I₂ ) 5-I₁ 2+2=0 Again, applying Kirchhoff's second law for a closed loop D E F C D , we get - (I₁+I₂ ) 5-I₂ 2+2=0 On solving, we get I₁= 1 6 ~A and I₂= 1 6 ~A I=I₁+I₂= 1 6 + 1 6 = 1 3 ~A