When a current is passed in a conductor, 5^ C rise in temperature is observed. If the strength of current is made thrice, rise in temperature will be

Step-by-step solution

Joule heating in a wire, H=I^2 R t For given R and t, H I^2 H₁ H₂ = I₁^2 I₂^2 Also, H=m s T For given m and s, H T H₁ H₂ = T₁ T₂ For eqn. (i) and (ii) I₁^2 I₂^2 = T₁ T₂ Here, I₁=I, T₁=5^ C , I₂=3 I aligned & T₂=? & ( I 3 I )^2= 5 T₂ or T₂=45^ C aligned