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NEET2008PhysicsCurrent ElectricityActual

The curve between ( _e J T^2 ) and ( 1 T ) is

Correct answer

0

Step-by-step solution

We know that J=A T^2 e^ -b / T J T^2 =A e^ -b / T Taking log both side, we get _e J T^2 = _e (A e^ -b / T ) _e J T^2 = _e A- b T Comparing with y=m x+C we get correct option (a).

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