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NEET2011PhysicsCurrent ElectricityActual

In the circuit shown the value of I in ampere is

Options

  1. A1
  2. B0.60
  3. C0.4
  4. D1.5

Correct answer

C. 0.4

Step-by-step solution

So net resistance, R=2.4+1.6=4.0 Therefore, current from the battery, i= V R = 4 4 =1 ~A Now from the circuit (b), aligned & 4 I^ =6 I & I^ = 3 2 I aligned But, i=I+I^ =I+ 3 2 I= 5 2 I array lc & 1= 5 2 I & I= 2 5 =0.4 ~A array

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