For the AC circuit shown below, phase difference between emf and current is $\frac{\pi}{4}$ radian as shown in the graph. If the impedance of the circuit is $1414 \Omega$ , then the values of $P$ and $Q$ are

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For the AC circuit shown below, phase difference between emf and current is (π)/(4) radian as shown in the graph. If the impedance of the circuit is 1414 , then the values of P and Q are

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Correct answer: A. 1 k , 10 μ F

In the shown figure, current is ahead of voltage, so its a R C circuit, so P is a resistor and Q is a capacitor. Now, in R C circuit, Z= R^2+X_C^2 For simple solution, Given aligned & =1000 2 & =1000 1+1 & = (1000)^2+(1000)^2 X_C & =1000 R=1000 Now, _C & =(1)/(ω C) =(1)/(ω X_C) & & =(1)/(100 × 1000)=10 μ F aligned Z=1414=1000 × 1.414

For the AC circuit shown below, phase difference between emf and...

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