In the circuit shown, the switch S₁ is closed at time t=0 and the switch S₂ is kept open. At some later time ( t ₀ ) , the switch S ₁ is opened and S ₂ is closed. the behaviour of the current I as a function of time ' t ' is given by:

Step-by-step solution

The current will grow for the time t =0 to t = t ₀ and after that decay of current takes place. Growth and decay of current is of exponential nature i = i ₀ (1- e ^ - t / ) during growth i = i _ e ^ - t / during decay