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NEET
Exam
NEET
Subject
Physics
Chapter
Alternating Current

NEET · Physics · Alternating Current

The current following through an inductance coil of self-inductance...

The current following through an inductance coil of self-inductance 6mH6 \mathrm{mH} at different time instants is as shown. The emf induced between t=20 st=20 \mathrm{~s} and t=40 st=40 \mathrm{~s} is nearly
The current following through an inductance coil of self-inductance 6 mH at different time instants is as shown. The

Options

  1. A2×10−2 V2 \times 10^{-2} \mathrm{~V}
  2. B3×10−2 V3 \times 10^{-2} \mathrm{~V}
  3. C4×10−3 V4 \times 10^{-3} \mathrm{~V}
  4. D30×10−4 V30 \times 10^{-4} \mathrm{~V}

Correct answer

D. 30×10−4 V30 \times 10^{-4} \mathrm{~V}

Step-by-step solution

As we know, Induced emf, ∣e∣=LdIdt|e|=L \frac{d I}{d t} Here, L=6mH=6×10−3HL=6 \mathrm{mH}=6 \times 10^{-3} \mathrm{H} From the given graph,
The current following through an inductance coil of self-inductance 6 mH at different time instants is as shown. The
∣e∣=L(I2−I1)(t2−t1)=L20=6×10−320=3×10−4 V\begin{aligned} |e| &=L \frac{\left(I_{2}-I_{1}\right)}{\left(t_{2}-t_{1}\right)} \\ &=\frac{L}{20}=\frac{6 \times 10^{-3}}{20}=3 \times 10^{-4} \mathrm{~V} \end{aligned}
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