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NEET
Exam
NEET
Subject
Physics
Chapter
Alternating Current

NEET · Physics · Alternating Current

The current graph for resonance in L C circuit is

The current graph for resonance in LCL C circuit isThe current graph for resonance in L C circuit isThe current graph for resonance in L C circuit isThe current graph for resonance in L C circuit isThe current graph for resonance in L C circuit is

Options

  1. AThe equivalent resistance across A and B is
  2. BThe equivalent resistance across A and B is
  3. CThe equivalent resistance across A and B is
  4. DThe equivalent resistance across A and B is

Correct answer

C. The equivalent resistance across A and B is

Step-by-step solution

In LC circuit, if XL=XCX_{\mathrm{L}}=X_{C} then ω=1LC\omega=\frac{1}{\sqrt{\mathrm{LC}}}\mathrm{I}_{0} \infty, \text{ so } \mathrm{Z}=\frac{\mathrm{E}_{0}}{\mathrm{I}_{0}}=0 As 1LC\frac{1}{\sqrt{\mathrm{LC}}} is the natural frequency of LC circuit, therefore for an LC circuit if the frequency of applied AC becomes equal to the natural frequency of an AC\mathrm{AC} circuit then the amplitude of current becomes infinite due to zero impedance.
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