In an RLC series circuit shown in figure, the readings of voltmeters ( V _ 1 ) and (V _ 2 ) are 100 V and 120 V respectively. The source voltage is 130 V. For this situation mark out the correct statement(s). (a)

Correct answer: A. a,c, d aligned & V_1= V_R^2+V_L^2 =100 (1) & V_C-V_L=120 (2) & 130= V_R^2+(V_L-V_C)^2 V_R=50 ~V & V_L=50 3 V=86.6 ~V ~&~ V_C=206.6 ~V & φ=(V_R)/(130)=(5)/(13) aligned )

NEET

Exam: NEET
Subject: Physics
Chapter: Alternating Current

NEET · Physics · Alternating Current

In an RLC series circuit shown in figure, the readings of...

In an RLC series circuit shown in figure, the readings of voltmeters (

\mathrm{V}}_{1}) and (\mathrm{V}

}_{2}) are 100 V and 120 V respectively. The source voltage is 130 V. For this situation mark out the correct statement(s). In an RLC series circuit shown in figure, the readings of voltmeters ( V _ 1 ) and (V _ 2 ) are 100 V and 120 V

In an RLC series circuit shown in figure, the readings of voltmeters ( V _ 1 ) and (V _ 2 ) are 100 V and 120 V

(a) Voltage across resistor, inductor and capacitor are (50

\mathrm{~V},

86.6

\mathrm{~V}

) and 206.6 V, respectively (b) Voltage across resistor, inductor and capacitor are (10

\mathrm{~V},

\mathrm{~V}

) and 30 V, respectively (c) Power factor of the circuit is (

\frac{5}{13}

) (d) The circuit is capacitive in nature

Options

Aa,c, d
Bb, c, d
C(\mathrm{c}, \mathrm{d})
DNone

Correct answer

A. a,c, d

Step-by-step solution

\begin{aligned} & V_1=\sqrt{V_R^2+V_L^2}=100 \quad \ldots (1) \\ & V_C-V_L=120 \quad \ldots (2) \\ & 130=\sqrt{V_R^2+\left(V_L-V_C\right)^2} \Rightarrow V_R=50 \mathrm{~V} \\ & V_L=50 \sqrt{3} V=86.6 \mathrm{~V} ~&~ V_C=206.6 \mathrm{~V} \\ & \cos \phi=\frac{V_R}{130}=\frac{5}{13} \end{aligned}

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