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NEET
Exam
NEET
Subject
Physics
Chapter
Alternating Current

NEET · Physics · Alternating Current

Match the following ( Currents r.m.s. values (1) x_ 0 ω t (i) x_ 0...

Match the following (
Currentsr.m.s. values
(1)x_{0}\sin \omega t(i)x_{0}
(2)x_{0}\sin \omega t \cos \omega t(ii)\tfrac{x_{0}}{\sqrt{2}}
(3)x_{0}\sin \omega t + x_{0}\cos \omega t(iii)\tfrac{x_{0}}{2\sqrt{2}}
)

Options

  1. A1 →\rightarrow (i),2 →\rightarrow (ii),3 →\rightarrow (iii)
  2. B1 →\rightarrow (ii), 2 →\rightarrow (iii),3 →\rightarrow (i)
  3. C1 →\rightarrow (i),2 →\rightarrow (iii),3 →\rightarrow (ii)
  4. DNone of these

Correct answer

B. 1 →\rightarrow (ii), 2 →\rightarrow (iii),3 →\rightarrow (i)

Step-by-step solution

1. (x_0 \sin (ω\omegat)) : This is a pure sinusoidal function. The r.m.s. value of a sinusoidal function (A \sin (ω\omegat)) is (A / 2\sqrt{2}). So, the r.m.s. value of (x_0 \sin (ω\omegat)) is (x_0 / 2\sqrt{2}). 2. (x_0 \sin (ω\omegat) \cos (ω\omegat)) : Using the trigonometric identity (\sin (2 ω\omegat)=2 \sin (ω\omegat) \cos (ω\omegat)), this can be rewritten as (x02sin⁡(\frac{x_0}{2} \sin (2 ω\omegat)), which is again a sinusoidal function. The r.m.s. value will be (x022\frac{x_0}{2 \sqrt{2}}). 3. (x_0 \sin (ω\omegat)+x_0 \cos (ω\omegat)) : This is a sum of two sinusoidal functions. The r.m.s. value of such a sum can befound by using 2 r.m.s. (=(x02)2+(x02)2=\sqrt{\left(\frac{x_0}{\sqrt{2}}\right)^2+\left(\frac{x_0}{\sqrt{2}}\right)^2}=). Now, match the r.m.s. values: 1. (x_0 \sin (ω\omegat) → x_0 / 2→\sqrt{2} \rightarrow) (ii) 2. (x_0 \sin (ω\omegat) \cos (ω\omegat) → x_0 / 2 2→\sqrt{2} \rightarrow) (iii) 3. (x_0 \sin (ω\omegat)+x_0 \cos (ω\omegat) → x_0 →) (i) The correct matching is: (c) 1 . (ii), 2. (iii), 3. (i)
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