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NEETPhysicsAlternating Current

Match List-I with List-II for a sinusoidal alternating voltage having peak value V₀ . List-I List-II (A) RMS Voltage (I) 2V₀ (B) Mean Voltage over half cycle (II) Zero (C) Mean Voltage over full cycle (III) 2V₀ (D) Peak-to-Peak Voltage (IV) V₀ 2 Choose the correct answer from the options given below:

Options

  1. A(A)-(IV), (B)-(III), (C)-(II), (D)-(I)
  2. B(A)-(III), (B)-(IV), (C)-(II), (D)-(I)
  3. C(A)-(IV), (B)-(III), (C)-(I), (D)-(II)
  4. D(A)-(IV), (B)-(I), (C)-(II), (D)-(III)

Correct answer

A. (A)-(IV), (B)-(III), (C)-(II), (D)-(I)

Step-by-step solution

(A) The RMS voltage for a sinusoidal wave is given by V_ rms = V₀ 2 . (B) The mean voltage over a half cycle is V_ mean = 2V₀ . (C) The mean voltage over a full cycle is zero because the positive and negative half cycles cancel each other out. (D) The peak-to-peak voltage is the difference between the positive peak and the negative peak, which is V₀ - (-V₀) = 2V₀ . Therefore, the correct matching is (A)-(IV), (B)-(III), (C)-(II), (D)-(I). Answer: (A)-(IV), (B)-(III), (C)-(II), (D)-(I)

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