A plot of current amplitude versus angular frequency for a series L-C-R circuit shows a peak at an angular frequency of 100 rad s ⁻¹ . The two points on the curve where the current amplitude is 1 2 times the peak value correspond to angular

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A plot of current amplitude versus angular frequency for a series L-C-R circuit shows a peak at an angular frequency of 100 rad s ⁻¹ . The two points on the curve where the current amplitude is 1 2 times the peak value correspond to angular frequencies of 90 rad s ⁻¹ and 110 rad s ⁻¹ . If the circuit contains a 0.5 H inductor, what is the resistance of the circuit?

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Correct answer: C. 10

The bandwidth of the series L-C-R circuit is the difference between the half-power angular frequencies. Bandwidth = ₂ - ₁ = 110 - 90 = 20 rad s ⁻¹ . The formula for bandwidth is = R L . Substituting the given values: 20 = R 0.5 R = 20 0.5 = 10 . Answer: 10

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