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NEETPhysicsAlternating Current

A pure inductor of inductance 2 H is connected to a 220 V , 50 Hz AC supply. The rms value of the current in the circuit is:

Options

  1. A1.1 A
  2. B2.2 A
  3. C1.1 2 A
  4. D2.2 A

Correct answer

A. 1.1 A

Step-by-step solution

The inductive reactance of the circuit is given by X_L = 2 f L . Substituting the given values: X_L = 2 50 ( 2 ) = 200 According to Ohm's law for AC circuits, the rms current is: I_ rms = V_ rms X_L I_ rms = 220 200 = 1.1 A Answer: 1.1 A

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