Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
NEETPhysicsAlternating Current

Given below are two statements: one is labelled as Assertion and the other is labelled as Reason. Assertion: When an AC voltage V = 260 (500 t) V is applied to a series LCR circuit with L = 160 mH, C = 10 , F, and R = 50 , , the peak current in the circuit is 2 A. Reason: In this circuit, the voltage leads the current because the inductive reactance is greater than the capacitive reactance. In the light of the above

Options

  1. ABoth Assertion and Reason are correct and Reason is the correct explanation for Assertion.
  2. BAssertion is correct but Reason is incorrect.
  3. CBoth Assertion and Reason are correct but Reason is not the correct explanation for Assertion.
  4. DAssertion is incorrect but Reason is correct.

Correct answer

B. Assertion is correct but Reason is incorrect.

Step-by-step solution

From the given equation V = 260 (500 t) V, we have V_m = 260 V and = 500 rad/s. The inductive reactance is X_L = L = 500 160 10⁻³ = 80 , . The capacitive reactance is X_C = 1 C = 1 500 10 10⁻⁶ = 1 5 10⁻³ = 200 , . The impedance is Z = R^2 + (X_L - X_C)^2 = 50^2 + (80 - 200)^2 = 50^2 + (-120)^2 = 130 , . The peak current is I_m = V_m Z = 260 130 = 2 A. Thus, the Assertion is correct. For the Reason: Since X_C (200 , ) > X_L (80 , ) , the circuit is predominantly capacitive. In a capacitive circuit, the current leads

Practice Alternating Current on Quantrex Academy →

More from Alternating Current

A step down transformer connected to an a.c. mains of 220 V is made to operate at 5.5 V, 44 W lamp. The current in the primary circuit is (Ignore power losses) 2026Which phasor diagram represents LCR circuit at resonance? 2026For an R-L series circuit, the power factor is 3 2 , for R-L frequency f Hz. If the frequency doubles, the new power factor will be 2026In an AC circuit, the current is I = 100 (5t) A. The value of I_ rms is 2026The ratio of power factor of purely resistive circuit to purely reactive circuit is ( 0^ = 1 and 90^ = 0 ) 2026In an LCR series circuit, at resonance, 2026In an AC circuit, E and I are given by E = 150 (150t) V and I = 150 (150t + 3 ) A. The power dissipated in the circuit is (60)^ = 1/2 2026A series LCR circuit is connected across a source E of e.m.f. E=15 (50 t- 3 ) . The current from the supply is I=5 (50 t+ 6 ) . The impedance of the circuit and the phase differenc 2026 Full Alternating Current list All NEET PYQs