Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
NEETPhysicsAlternating Current

Two ideal capacitors C₁ and C₂ are connected to two different AC sources. The first circuit has capacitance C₁ = C , rms voltage V₁ = V , and frequency f₁ = f . The second circuit has capacitance C₂ = C 2 , rms voltage V₂ = 2V , and frequency f₂ = 2f . The ratio of the rms currents I₁ : I₂ in the two circuits is:

Options

  1. A2 : 1
  2. B1 : 4
  3. C1 : 2
  4. D1 : 1

Correct answer

C. 1 : 2

Step-by-step solution

The rms current in a purely capacitive circuit is given by I = V X_C . Since X_C = 1 2 f C , the current can be written as I = V(2 f C) . For the first circuit: I₁ = V(2 f C) For the second circuit: I₂ = (2V)(2 2f C 2 ) = 2V(2 f C) = 2I₁ Therefore, the ratio of the rms currents is I₁ : I₂ = 1 : 2 . Answer: 1 : 2

Practice Alternating Current on Quantrex Academy →

More from Alternating Current

A step down transformer connected to an a.c. mains of 220 V is made to operate at 5.5 V, 44 W lamp. The current in the primary circuit is (Ignore power losses) 2026Which phasor diagram represents LCR circuit at resonance? 2026For an R-L series circuit, the power factor is 3 2 , for R-L frequency f Hz. If the frequency doubles, the new power factor will be 2026In an AC circuit, the current is I = 100 (5t) A. The value of I_ rms is 2026The ratio of power factor of purely resistive circuit to purely reactive circuit is ( 0^ = 1 and 90^ = 0 ) 2026In an LCR series circuit, at resonance, 2026In an AC circuit, E and I are given by E = 150 (150t) V and I = 150 (150t + 3 ) A. The power dissipated in the circuit is (60)^ = 1/2 2026A series LCR circuit is connected across a source E of e.m.f. E=15 (50 t- 3 ) . The current from the supply is I=5 (50 t+ 6 ) . The impedance of the circuit and the phase differenc 2026 Full Alternating Current list All NEET PYQs