NEET2009PhysicsAlternating CurrentActual
In a series L C R circuit, the voltage across the resistance, capacitance and inductance is 10 ~V each. If the capacitance is short circuited the voltage across the inductance will be
Options
- A10 ~V
- B10 2 ~V
- C10 / 2 ~V
- D20 ~V
Correct answer
C. 10 / 2 ~V
Step-by-step solution
aligned & As V_R=V_L=V_C & R =X_L=X_ C, Z=R & V=I R=10 volt aligned When capacitor is short circuited, Z= R^2+X_L^2 = R^2+R^2 =R 2 New current I^ =V / Z=V / R 2 = 10 R 2 Potential drop across inductance =I^ X_L=I^ R= 10 R R 2 = 10 2 volt