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NEET2016PhysicsAlternating CurrentActual

A transformer having efficiency of 75 % is working on 220 V and 4.4 kW power supply. If the current in the secondary coil is 5 A . What will be the voltage across secondary coil and the current in primary coil?

Options

  1. AV_S=220 ~V , i_P=20 ~A
  2. BV_S=660 ~V , i_P=15 ~A
  3. CV_S=660 ~V , i_P=20 ~A
  4. DV_S=220 ~V , i_P=15 ~A

Correct answer

C. V_S=660 ~V , i_P=20 ~A

Step-by-step solution

Given, P_ in =4.4 ~kW , V_p=220 ~V , i_s=5 ~A , V_s= ? We know that, i_P= P_ in V_P = 4.4 10^3 220 =20 ~A Efficiency, = Output power Input power Percentage efficiency = P_ out P_ in 100 aligned 75 % & =100 P_ out 4.4 10^3 P_ out & = 75 4.4 10^3 100 & =3300 ~W P_ out & =V_S i_S V_S & = 3300 5 =660 ~V aligned

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