A solar panel of area 10 cm^2 is exposed to sunlight having an...

The total energy $E$ received by a surface is given by the product of intensity $I$, area $A$, and time $t$:

$E = I \times A \times t$

Given:
$I = 50 \text{ W cm}^{-2}$
$A = 10 \text{ cm}^2$
$E = 3 \times 10^5 \text{ J}$

First, calculate the total power received by the panel:
$P = I \times A = 50 \text{ W cm}^{-2} \times 10 \text{ cm}^2 = 500 \text{ W}$

Now, substitute the power into the energy equation to find the time in seconds:
$t = \dfrac{E}{P} = \dfrac{3 \times 10^5 \text{ J}}{500 \text{ W}} = 600 \text{ s}$

Finally, convert the time from seconds to minutes:
$t = \dfrac{600}{60} \text{ minutes} = 10 \text{ minutes}$

Answer: $10$