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NEET
Exam
NEET
Subject
Physics
Chapter
Electromagnetic Waves

NEET · Physics · Electromagnetic Waves

An electromagnetic wave of total intensity I is propagating in...

An electromagnetic wave of total intensity II is propagating in vacuum. If cc is the speed of light in vacuum, the average energy density of the magnetic field component of this wave is:

Options

  1. AIc\dfrac{I}{c}
  2. BIc2\dfrac{I}{c^2}
  3. C2Ic\dfrac{2I}{c}
  4. DI2c\dfrac{I}{2c}

Correct answer

D. I2c\dfrac{I}{2c}

Step-by-step solution

The total intensity II of an electromagnetic wave is related to its total average energy density uu by the equation:

I=ucI = u c

⇒u=Ic\Rightarrow u = \dfrac{I}{c}

In an electromagnetic wave, the total energy is shared equally between the electric and magnetic fields. Thus, the average energy density of the magnetic field (uBu_B) is exactly half of the total average energy density.

uB=u2=I2cu_B = \dfrac{u}{2} = \dfrac{I}{2c}

Answer: I2c\dfrac{I}{2c}
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