NEETPhysicsElectromagnetic Waves
An electromagnetic wave of total intensity I is propagating in vacuum. If c is the speed of light in vacuum, the average energy density of the magnetic field component of this wave is:
Options
- AI c
- BI c^2
- C2I c
- DI 2c
Correct answer
D. I 2c
Step-by-step solution
The total intensity I of an electromagnetic wave is related to its total average energy density u by the equation: I = u c u = I c In an electromagnetic wave, the total energy is shared equally between the electric and magnetic fields. Thus, the average energy density of the magnetic field ( u_B ) is exactly half of the total average energy density. u_B = u 2 = I 2c Answer: I 2c