An equiconcave lens made of glass with a refractive index of 1.5 has a power of -5 D . The magnitude of the radius of curvature of each of its surfaces is:

Step-by-step solution

The power of a lens is related to its focal length by P = 1 f , where f is in meters. Using the Lens Maker's formula: P = ( - 1) ( 1 R₁ - 1 R₂ ) For an equiconcave lens, by sign convention, the first surface is concave ( R₁ = -R ) and the second surface is convex towards the incident light from inside the lens ( R₂ = +R ). Substituting the values into the formula: -5 = (1.5 - 1) ( 1 -R - 1 R ) -5 = 0.5 ( -2 R ) -5 = -1 R R = 1 5 m Converting to centimeters: R = 0.2 m = 20 cm The magnitude of the radius of curvature