NEETPhysicsRay Optics
Match List-I with List-II for an equiconvex lens of power P . List-I (Modification) List-II (Resulting Power) (A) Cut into two equal halves along the principal axis (power of one part) (I) P 2 (B) Cut into two equal halves perpendicular to the principal axis (power of one part) (II) 0 (C) Immersed in a liquid having the same refractive index as the lens material (III) P (D) Two identical lenses placed in contact coax
Options
- A(A)-(I), (B)-(III), (C)-(II), (D)-(IV)
- B(A)-(III), (B)-(I), (C)-(IV), (D)-(II)
- C(A)-(III), (B)-(I), (C)-(II), (D)-(IV)
- D(A)-(I), (B)-(III), (C)-(IV), (D)-(II)
Correct answer
C. (A)-(III), (B)-(I), (C)-(II), (D)-(IV)
Step-by-step solution
(A) When cut along the principal axis, the radii of curvature remain unchanged. Hence, the focal length and power remain the same ( P ). (B) When cut perpendicular to the principal axis, the lens becomes plano-convex. One radius of curvature becomes infinity, doubling the focal length and halving the power ( P 2 ). (C) When immersed in a liquid of the same refractive index, the relative refractive index becomes 1. The lens acts as a plane glass plate with infinite focal length and zero power ( 0 ). (D) When two ide