A ray of light is incident at an angle of 2^ on one face of a thin prism of prism angle 5^ . If the refractive index of the material of the prism is 1.6 , then the angle of emergence of the ray is

Step-by-step solution

For a thin prism, the angle of deviation is given by: = ( - 1)A = (1.6 - 1) 5^ = 0.6 5^ = 3^ The general relation between the angle of incidence i , angle of emergence e , prism angle A , and deviation is: i + e = A + Substituting the given values: 2^ + e = 5^ + 3^ 2^ + e = 8^ e = 6^ Alternatively, using the small angle approximation directly: i + e = A 2^ + e = 1.6 5^ 2^ + e = 8^ e = 6^ Answer: 6^