A 2.0 ~cm tall object is placed 15 ~cm in front of a concave mirror of focal length 10 ~cm . What is the size and nature of the image?

Step-by-step solution

According to new cartesian sign convention, Object distance, u=-15 ~cm Focal length of the concave mirror, f=-10 ~cm Height of the object, h_O=2 ~cm According to mirror formula, 1 v + 1 u = 1 f 1 v = 1 f - 1 u = 1 -10 - 1 -15 = 1 -10 + 1 15 or v=-30 ~cm . The image is formed at a distance of 30 ~cm from the mirror on the same side of the object. It is a real image. Magnification of the mirror, m= -v u = h_I h_O -(-30) -15 = h_I 2 h_I=-4 ~cm . Negative sign shows that image is inverted. The image is real, inverted,