NEET2010PhysicsRay OpticsActual
For a person near point of vision is 100 ~cm . Then the power of lens he must wear so as to have normal vision, should be
Options
- A+1 D
- B-1 D
- C+3 D
- D-3 D
Correct answer
C. +3 D
Step-by-step solution
The power of lens P= 1 f = 1 v - 1 u = [ 1 25 - 1 N.P. ] where N.P. = Near point of vision aligned & P= [ 1 25 - 1 100 ] & P= 4-1 100 = 3 100 ~cm = 3 1 ~m =3 D aligned