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NEET
Exam
NEET
Subject
Physics
Chapter
Wave Optics

NEET · Physics · Wave Optics

Match List-I with List-II regarding the interference pattern...

Match List-I with List-II regarding the interference pattern produced by two coherent sources:

List-I (Path/Phase difference)List-II (Fringe type)
(A) Δx=0\Delta x = 0(I) First minimum
(B) Δx=λ2\Delta x = \dfrac{\lambda}{2}(II) Central maximum
(C) Δϕ=2π\Delta \phi = 2\pi(III) Third minimum
(D) Δϕ=5π\Delta \phi = 5\pi(IV) First maximum

Choose the correct answer from the options given below:

Options

  1. A(A)-(IV), (B)-(III), (C)-(II), (D)-(I)
  2. B(A)-(II), (B)-(IV), (C)-(I), (D)-(III)
  3. C(A)-(II), (B)-(III), (C)-(IV), (D)-(I)
  4. D(A)-(II), (B)-(I), (C)-(IV), (D)-(III)

Correct answer

D. (A)-(II), (B)-(I), (C)-(IV), (D)-(III)

Step-by-step solution

The phase difference Δϕ\Delta \phi and path difference Δx\Delta x are related by Δϕ=2πλΔx\Delta \phi = \dfrac{2\pi}{\lambda} \Delta x.

For (A): Δx=0\Delta x = 0 corresponds to a phase difference of zero, which is the condition for the central maximum. Hence, (A) matches with (II).

For (B): Δx=λ2\Delta x = \dfrac{\lambda}{2} corresponds to Δϕ=π\Delta \phi = \pi. This satisfies the condition for the first minimum, Δϕ=(2n−1)π\Delta \phi = (2n-1)\pi with n=1n=1. Hence, (B) matches with (I).

For (C): Δϕ=2π\Delta \phi = 2\pi satisfies the condition for constructive interference Δϕ=2nπ\Delta \phi = 2n\pi with n=1n=1, which is the first maximum. Hence, (C) matches with (IV).

For (D): Δϕ=5π\Delta \phi = 5\pi satisfies the condition for destructive interference Δϕ=(2n−1)π\Delta \phi = (2n-1)\pi with n=3n=3, which is the third minimum. Hence, (D) matches with (III).

The correct matching is (A)-(II), (B)-(I), (C)-(IV), (D)-(III).

Answer: (A)-(II), (B)-(I), (C)-(IV), (D)-(III)
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