Two separate Young's double slit experiments are performed. In the first experiment, light of wavelength 500 nm is used with a slit separation d and screen distance D . In the second experiment, light of wavelength 600

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Correct answer: A. 5 : 24

Fringe width in a Young's double slit experiment is given by

\beta = \dfrac{\lambda D}{d}

.

For the first experiment:

\beta_1 = \dfrac{\lambda_1 D_1}{d_1} = \dfrac{500 \text{ nm} \times D}{d}

For the second experiment:

\beta_2 = \dfrac{\lambda_2 D_2}{d_2} = \dfrac{600 \text{ nm} \times (2D)}{\left(\dfrac{d}{2}\right)} = \dfrac{2400 \text{ nm} \times D}{d}

Taking the ratio of the two fringe widths:

\dfrac{\beta_1}{\beta_2} = \dfrac{\left(\dfrac{500 D}{d}\right)}{\left(\dfrac{2400 D}{d}\right)} = \dfrac{500}{2400} = \dfrac{5}{24}

Thus, the ratio is

5 : 24

.

Answer:

5 : 24

Two separate Young's double slit experiments are performed. In the...

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