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AIIMS 2013
Exam
AIIMS
Year
2013
Subject
Chemistry
Chapter
Structure of Atom

AIIMS 2013 · Chemistry · Structure of Atom

A particle is moving 3 times faster than the speed of electron. If...

A particle is moving 3 times faster than the speed of electron. If the ratio of wavelength of particle and electron is 1.8×10−41.8 \times 10^{-4}, then particle is

Options

  1. Aneutron
  2. Bα\alpha-particle
  3. Cdeuteron
  4. Dtritium

Correct answer

A. neutron

Step-by-step solution

Given :λparticle λelectron =1.8×10−4: \frac{\lambda_{\text{particle }}}{\lambda_{\text{electron }}}=1.8 \times 10^{-4} and vparticle velectron =3\frac{v_{\text{particle }}}{v_{\text{electron }}}=3 According to de-Broglie equation, λ=hmvλparticle λelectron =hmparticle ×vparticle ×melectron ×velectron h=melectron mparticle ×velectron vparticle ⇒1.8×10−4=9.1×10−31kgmparticle ×13mparticle =9.1×10−311.8×10−4×3=1.6852×10−27kgActualmassofneutronis\lambda=\frac{h}{m v} \frac{\lambda_{\text{particle }}}{\lambda_{\text{electron }}}=\frac{h}{m_{\text{particle }} \times v_{\text{particle }}} \times \frac{m_{\text{electron }} \times v_{\text{electron }}}{h} =\frac{m_{\text{electron }}}{m_{\text{particle }}} \times \frac{v_{\text{electron }}}{v_{\text{particle }}} \Rightarrow 1.8 \times 10^{-4}=\frac{9.1 \times 10^{-31} \mathrm{ kg}}{m_{\text{particle }}} \times \frac{1}{3} m_{\text{particle }}=\frac{9.1 \times 10^{-31}}{1.8 \times 10^{-4} \times 3} =1.6852 \times 10^{-27} \mathrm{ kg} Actual mass of neutron is1.67493 \times 10^{-27} kg\mathrm{ kg}. Hence, the particle is neutron.
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