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JIPMER 2014

Exam: JIPMER
Year: 2014
Subject: Chemistry
Chapter: Structure of Atom

JIPMER 2014 · Chemistry · Structure of Atom

If n=6 , the correct sequence for filling of electrons will be

If

n=6

, the correct sequence for filling of electrons will be

Options

A $n s \longrightarrow(n-1) d \longrightarrow(n-2) f \longrightarrow n p$
B $n s \longrightarrow(n-2) f \longrightarrow n p \longrightarrow(n-1) d$
C $n s \longrightarrow n p \longrightarrow(n-1) d \longrightarrow(n-2) f$
D $n s \longrightarrow(n-2) f \longrightarrow(n-1) d \longrightarrow n p$

Correct answer

D. $n s \longrightarrow(n-2) f \longrightarrow(n-1) d \longrightarrow n p$

Step-by-step solution

For

n-6

olectron aro filled as

6 s \rightarrow 4 f \rightarrow 5 d \rightarrow 6 p

This is because electron first enters in that orbitals for which

(n+l)

is lower. In case, if

(n+I)

is same, it goes first in that orbital for which

n

is lower.

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