In a Geiger-Marsden -particle scattering experiment, the number of -particles scattered at an angle of 60^ is N per minute. What will be the number of -particles scattered at an angle of 120^ in the same time interval?

Step-by-step solution

According to Rutherford's scattering formula, the number of -particles scattered at an angle is given by: N( ) 1 ^4( /2) Taking the ratio of the number of particles scattered at 120^ and 60^ : N(120^ ) N(60^ ) = ^4(60^ /2) ^4(120^ /2) N(120^ ) N = ^4(30^ ) ^4(60^ ) N(120^ ) N = (1/2)^4 ( 3 /2)^4 = 1/16 9/16 = 1 9 Therefore, N(120^ ) = N 9 . Answer: N 9