An electron in a hydrogen atom has a total energy of -0.85 eV . What is the angular momentum of the electron in this state?

Step-by-step solution

The total energy of an electron in the n^ th orbit of a hydrogen atom is given by E = -13.6 n^2 eV . Given E = -0.85 eV , we have: -13.6 n^2 = -0.85 n^2 = 13.6 0.85 = 16 n = 4 According to Bohr's postulate, the angular momentum of the electron is L = nh 2 . Substituting n = 4 , we get: L = 4h 2 = 2h Answer: 2h