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Match List-I with List-II regarding the energies of an electron in a hydrogen-like atom: List-I List-II (A) KE TE (I) 2 (B) PE KE (II) 1 (C) PE TE (III) -1 (D) KE + PE TE (IV) -2 Choose the correct answer from the options given below:

Options

  1. A(A)-(II), (B)-(I), (C)-(IV), (D)-(III)
  2. B(A)-(III), (B)-(I), (C)-(IV), (D)-(II)
  3. C(A)-(III), (B)-(IV), (C)-(I), (D)-(II)
  4. D(A)-(IV), (B)-(III), (C)-(II), (D)-(I)

Correct answer

C. (A)-(III), (B)-(IV), (C)-(I), (D)-(II)

Step-by-step solution

For an electron in a hydrogen-like atom, the relationships between kinetic energy (KE), potential energy (PE), and total energy (TE) are: TE = - KE and PE = 2 TE = -2 KE (A) KE TE = KE - KE = -1 (Matches III) (B) PE KE = -2 KE KE = -2 (Matches IV) (C) PE TE = 2 TE TE = 2 (Matches I) (D) KE + PE TE = TE TE = 1 (Matches II) Thus, the correct matching is (A)-(III), (B)-(IV), (C)-(I), (D)-(II). Answer: (A)-(III), (B)-(IV), (C)-(I), (D)-(II)

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