In hydrogen atom, electron excites from ground state to higher energy state and its orbital velocity is reduced to ((1)/(3))^ rd of its initial value. The radius of the orbit in the ground state is R . The radius of the

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Correct answer: D. 9 R

where subscripts h and g denotes higher energy state and ground state. Orbital velocity of electron in the n^ th orbit is v_n=(e^2)/(2 _0 n h) or v_n (1)/(n) Equating eqns. (i) and (ii), we get n=3 Radius of n^ th orbit is r_n=(n^2 h^2 _0)/(π e^2 m^2) or r_n n^2 aligned (r_3)/(r_1) & =((3)^2)/((1)^2)=9 r_3 & =9 r_1=9 R ( r_1=R( Given )) aligned

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