Ratio of longest wavelengths corresponding to Lyman and Balmer series in hydrogen spectrum is

Step-by-step solution

The transition equation for Lyman series is given by 1 =R ( 1 1^2 - 1 n^2 ) for largest wavelength, n=2 . 1 _ =R ( 1 1^2 - 1 2^2 ) The transition equation for Balmer series is given by 1 =R ( 1 2^2 - 1 n^2 ) for largest wavelength, n = 3 1 _ =R ( 1 2^2 - 1 3^2 ) Therefore, _ L_ _ B_ = ( 1 2^2 - 1 3^2 ) ( 1 1^2 - 1 2^2 ) = 5 36 3 4 = 5 27