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There are four Vernier seales, whose specifications are given in column-1 and the least count is given in Column-II. Match the Columns-1 and II with correct specification and corresponding least count ( ( s = ) value of main scale division, ( n = ) number of marks on Vernier). Assume ( ( n -1 )) main scale divisions are equal to n Vernier divisions. ( array |l|l|l|l| & Column-I & & Column-II A. & s=1 ~mm , n =10 & P.

Options

  1. AA-(Q); B-(R); C-(P); D-(S)
  2. BA-(R); B-(P); C-(S); D-(Q)
  3. CA-(P); B-(Q); C-(R); D-(S)
  4. DNone of these

Correct answer

B. A-(R); B-(P); C-(S); D-(Q)

Step-by-step solution

Least count (LC) of a Vernier (=s / n ), where (s= ) main scale division (MSD) value, ( n = ) number of Vernier divisions. - (A: s=1 ~mm , n=10 L C=1 / 10=0.1 ~mm ) R - B: ( s =0.5 ~mm , n =10 LC =0.5 / 10=0.05 mm P ) - ( C : s =0.5 ~mm , n =20 LC =0.5 / 20= 0.025 ~mm ~S ) - ( D : s =1 ~mm , n =100 LC =1 / 100=0.01 mm Q ) Hence option (2).

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