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NEET
Exam
NEET
Subject
Physics
Chapter
Experimental Physics

NEET · Physics · Experimental Physics

Match List-I with List-II. List-I List-II A) 1^ I) 57.3^ B) 1' II)...

Match List-I with List-II.






















List-I List-II
A) 1∘1^\circ I) 57.3∘57.3^\circ
B) 1′1' II) 1.745×10−2 rad1.745 \times 10^{-2} \text{ rad}
C) 1′′1'' III) 2.91×10−4 rad2.91 \times 10^{-4} \text{ rad}
D) 1 rad1 \text{ rad} IV) 4.85×10−6 rad4.85 \times 10^{-6} \text{ rad}


Choose the correct answer from the options given below:

Options

  1. AA-II, B-III, C-IV, D-I
  2. BA-I, B-III, C-IV, D-II
  3. CA-II, B-IV, C-III, D-I
  4. DA-II, B-I, C-IV, D-III

Correct answer

A. A-II, B-III, C-IV, D-I

Step-by-step solution

To find the correct matching, we convert the units step by step:

1∘=π180 rad≈1.745×10−2 rad1^\circ = \dfrac{\pi}{180} \text{ rad} \approx 1.745 \times 10^{-2} \text{ rad} (A matches II)

1′=(160)∘=1.745×10−260 rad≈2.91×10−4 rad1' = \left(\dfrac{1}{60}\right)^\circ = \dfrac{1.745 \times 10^{-2}}{60} \text{ rad} \approx 2.91 \times 10^{-4} \text{ rad} (B matches III)

1′′=(160)′=2.91×10−460 rad≈4.85×10−6 rad1'' = \left(\dfrac{1}{60}\right)' = \dfrac{2.91 \times 10^{-4}}{60} \text{ rad} \approx 4.85 \times 10^{-6} \text{ rad} (C matches IV)

1 rad=180∘π≈57.3∘1 \text{ rad} = \dfrac{180^\circ}{\pi} \approx 57.3^\circ (D matches I)

Therefore, the correct matching is A-II, B-III, C-IV, D-I.

Answer: A-II, B-III, C-IV, D-I
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