A screw gauge has a pitch of 0.5 mm and 50 divisions on its circular scale. When used to measure the thickness of a glass plate, the main scale reading is 2.0 mm and the total measured thickness is 2.34 mm . The reading

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Quantrex Academy · Accepted Answer

Correct answer: A. 34

Least count (LC) of the screw gauge is given by:

\text{LC} = \dfrac{\text{Pitch}}{\text{Number of circular scale divisions}}

\text{LC} = \dfrac{0.5\text{ mm}}{50} = 0.01\text{ mm}

The total reading is given by the formula:

\text{Total Reading} = \text{Main Scale Reading (MSR)} + (\text{Circular Scale Reading (CSR)} \times \text{LC})

Substituting the given values:

2.34\text{ mm} = 2.0\text{ mm} + (\text{CSR} \times 0.01\text{ mm})

0.34\text{ mm} = \text{CSR} \times 0.01\text{ mm}

\text{CSR} = \dfrac{0.34}{0.01} = 34

The coinciding division on the circular scale is

34

.

Answer:

34

A screw gauge has a pitch of 0.5 mm and 50 divisions on its...

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