A screw gauge has a pitch of 0.5 mm and 50 divisions on its circular scale. When used to measure the thickness of a glass plate, the main scale reading is 2.0 mm and the total measured thickness is 2.34 mm . The reading on the circular scale (number of coinciding divisions) is:

Step-by-step solution

Least count (LC) of the screw gauge is given by: LC = Pitch Number of circular scale divisions LC = 0.5 mm 50 = 0.01 mm The total reading is given by the formula: Total Reading = Main Scale Reading (MSR) + ( Circular Scale Reading (CSR) LC ) Substituting the given values: 2.34 mm = 2.0 mm + ( CSR 0.01 mm ) 0.34 mm = CSR 0.01 mm CSR = 0.34 0.01 = 34 The coinciding division on the circular scale is 34 . Answer: 34