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The least count of a vernier callipers is given as x mm. It is observed that N divisions of its vernier scale coincide exactly with (N-2) divisions of the main scale. The value of one main scale division ( 1 MSD ) is:

Options

  1. ANx
  2. BNx 2
  3. Cx N
  4. D(N-2)x N

Correct answer

B. Nx 2

Step-by-step solution

The least count (LC) of a vernier callipers is defined as: LC = 1 MSD - 1 VSD Given the coincidence relation: N VSD = (N-2) MSD 1 VSD = N-2 N MSD Substitute this into the least count formula: LC = 1 MSD - ( N-2 N ) MSD LC = (1 - N-2 N ) MSD LC = ( N - N + 2 N ) MSD = 2 N MSD We are given that LC = x . Therefore: x = 2 N MSD Rearranging to find the value of 1 MSD : 1 MSD = Nx 2 Answer: Nx 2

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