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A vernier calliper has a least count of C cm . It is given that N divisions of the vernier scale coincide with (N-1) divisions of the main scale. The number of divisions in 1 cm on the main scale is

Options

  1. A1 C
  2. BN C
  3. CC N
  4. D1 NC

Correct answer

D. 1 NC

Step-by-step solution

The least count (LC) of a vernier calliper is the difference between one main scale division (MSD) and one vernier scale division (VSD). Given that N VSD = (N-1) MSD, we can write: 1 VSD = N-1 N MSD Therefore, the least count is: LC = 1 MSD - 1 VSD LC = 1 MSD - N-1 N MSD = 1 N MSD We are given that the least count is C cm , so: 1 N MSD = C cm 1 MSD = N C cm The number of divisions per cm on the main scale is the reciprocal of the length of one main scale division: Number of divisions per cm = 1 1 MSD = 1 NC Answer:

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