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Graph betwen stopping potential for most energetic emitted photoelectrons ( V _ s ) with frequency (v) of incident radiation on metal is given below. Value of AB / BC , in graph is [where h = plank's constant, e = electronic charge]

Options

  1. Ah
  2. Be
  3. Ch / e
  4. De / h

Correct answer

C. h / e

Step-by-step solution

By Einstein's photoelectric equation ( aligned & K E_ =e V_s=h v-h v₀ & V_s= ( h e ) v- h v₀ e aligned ) Graph of (V_s ) with ( v ) is straight line whose slope (= h e ) Slope of graph (= A B B C A B B C = h e )

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