An electron of mass m and charge e initially at rest gets accelerated by a constant electric field E. The de-Broglie wavelength of the electron at time t is (h = Planck's constant)

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Correct answer: A. (h)/(eEt)

The force acting on the electron in a constant electric field is

F = eE

Since the electron is initially at rest, its momentum at time

t

is

p = Ft = eEt

The de-Broglie wavelength is given by

\lambda = \dfrac{h}{p}

Substituting the value of momentum, we get

\lambda = \dfrac{h}{eEt}

Answer:

\dfrac{h}{eEt}

An electron of mass m and charge e initially at rest gets...

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